3x^2/3-23x^1/3-8=0

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Solution for 3x^2/3-23x^1/3-8=0 equation: 


x in (-oo:+oo)

(3*x^2)/3-((23*x^1)/3)-8 = 0

(3*x^2)/3+(-23/3)*x-8 = 0

x^2-23/3*x-8 = 0

DELTA = (-23/3)^2-(-8*1*4)

DELTA = 817/9

DELTA > 0

x = ((817/9)^(1/2)+23/3)/(1*2) or x = (23/3-(817/9)^(1/2))/(1*2)

x = ((817/9)^(1/2)+23/3)/2 or x = (23/3-(817/9)^(1/2))/2

x in { (23/3-(817/9)^(1/2))/2, ((817/9)^(1/2)+23/3)/2 }

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